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AS Level physics accelaration question Watch

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    A pebble, released at rest from a canal bridge, took 0.9 seconds to hit the water. Calculate:
    a
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    A) The distance it fell before hitting the water and B) its speed just before hitting the water.
    Done part A: distance=0.5*gravity*time^2
    1/2*9.8*0.9^2=3.969m (=4m)
    Not sure how to do part B? Any help appreciated?
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    Use the suvat equation v = u + at.
    You have initial velocity (0ms-1), the time and the acceleration (g=9.81ms-2)

    Hope this helps.
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    Thanks
 
 
 
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