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# AS Level physics accelaration question

1. A pebble, released at rest from a canal bridge, took 0.9 seconds to hit the water. Calculate:
a
2. A) The distance it fell before hitting the water and B) its speed just before hitting the water.
Done part A: distance=0.5*gravity*time^2
1/2*9.8*0.9^2=3.969m (=4m)
Not sure how to do part B? Any help appreciated?
3. Use the suvat equation v = u + at.
You have initial velocity (0ms-1), the time and the acceleration (g=9.81ms-2)

Hope this helps.
4. Thanks

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