Find the volume of the solid generated when rotating the closed region between the curves y=8(x)^1/2 and y=x^2 fully about the y-axis
this what i've got so far...
y/8 = x^1/2
y^2/64 = x
x^2 = y^4/4096
their intersection is x=4, y=16
V= pi[y^5/5 - 4096y^2/2] with 4 at t and 0 at bottom of bracket
Is it really that intense? Would I cope?