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M1 Displacement Question Why do the distances total 46m? Ex 2C Q.14 [PLEASE HELP]

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    I managed to use SUVAT to find the distance S in terms of T for both balls A and B.

    The answers state that S(A) + S(B) = 46 such that both balls travel 46m in total.
    I'm struggling to comprehend how this can be the case.

    Help me please!!!
    Thanks!
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    Well at the point of collision their total displacement will have been 46 meters, because one is thrown down, and one is thrown up, so maybe one went 30 meters down and the other went 16 meters up, or one went 45 meters down and the other 1 meter up, where they collide the distance HAS to be 46 meters, or they wouldn't have collided
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    (Original post by iMacJack)
    Well at the point of collision their total displacement will have been 46 meters, because one is thrown down, and one is thrown up, so maybe one went 30 meters down and the other went 16 meters up, or one went 45 meters down and the other 1 meter up, where they collide the distance HAS to be 46 meters, or they wouldn't have collided
    Got it! Thanks.
 
 
 
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