C3 Maths Help Needed

Show that
cos2x/cosx+sinx = cosx - sinx
:?
Thanks

Cos2x = (cosx-sinx)(cosx+sinx)

Original post by Mr Moon Man

Cos2x = (cosx-sinx)(cosx+sinx)

I dont understand
how does

cos2x = ( cosx + sin x ) ( cosx - sinx)

Cos2x = (cosx)^2 - (sinx)^2 = (cosx - sinx)(cosx + sinx)

Original post by Mr Moon Man

Cos2x = (cosx)^2 - (sinx)^2 = (cosx - sinx)(cosx + sinx)

I get what you did at the end. you just took the difference of two squares but how does
cos2x = (cosx)^2-(sinx)^2
Thank you for helping

Original post by Why-_-Study-_-

I get what you did at the end. you just took the difference of two squares but how does
cos2x = (cosx)^2-(sinx)^2
Thank you for helping

Have you not done trig identities yet? Cos2x is one of the main ones

Original post by Mr Moon Man

Have you not done trig identities yet? Cos2x is one of the main ones

I understand it now
Cos ( 2A ) = cos^2 A - sin^2 A

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