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    Given that p is a constant such that 0 < p < 1, show that the equation

    px^2 + 2x + (1-p) = 0

    has two distinct roots


    b^2 - 4ac > 0

    2^2 - 4*p*(1-p) > 0

    4 - (-4p^2 + 4p) > 0

    4 + 4p^2 - 4p > 0

    however 4p^2 - 4p + 4 doesn't have any real roots, where did I go wrong?
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    (Original post by tammio)
    Given that p is a constant such that 0 < p < 1, show that the equation

    px^2 + 2x + (1-p) = 0

    has two distinct roots


    b^2 - 4ac > 0

    2^2 - 4*p*(1-p) > 0

    4 - (-4p^2 + 4p) > 0

    4 + 4p^2 - 4p > 0

    however 4p^2 - 4p + 4 doesn't have any real roots, where did I go wrong?
    Try completing the square with the discriminant
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    You haven't, the max value of P is 0.999.. and the smallest value is 0.0000....1, both of which when plugged into your equation result in your resulting inequality being solved hence there are 2 distinct roots, even if they are disgusting numbers.
    (Original post by tammio)
    Given that p is a constant such that 0 < p < 1, show that the equation

    px^2 + 2x + (1-p) = 0

    has two distinct roots


    b^2 - 4ac > 0

    2^2 - 4*p*(1-p) > 0

    4 - (-4p^2 + 4p) > 0

    4 + 4p^2 - 4p > 0

    however 4p^2 - 4p + 4 doesn't have any real roots, where did I go wrong?
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    do either of you do economics In really stuck on a question?
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    (Original post by Foodatastic)
    You haven't, the max value of P is 0.999.. and the smallest value is 0.0000....1, both of which when plugged into your equation result in your resulting inequality being solved hence there are 2 distinct roots, even if they are disgusting numbers.
    I should be more clear. Your inequality states that p^2 - p + 1 > 0, any value for P will result in a positive number hence the quadratic is solvable.
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    I do economics, I can help hopefully
    (Original post by Fairy5eva)
    do either of you do economics In really stuck on a question?
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    (Original post by Foodatastic)
    You haven't, the max value of P is 0.999.. and the smallest value is 0.0000....1, both of which when plugged into your equation result in your resulting inequality being solved hence there are 2 distinct roots, even if they are disgusting numbers.
    Thanks very much
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    Name:  IMG_0098.jpg
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    (Original post by Foodatastic)
    I do economics, I can help hopefully
    Do you know how to do b and c?
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    (Original post by Fairy5eva)
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    Do you know how to do b and c?
    Not too sure, I suspect we do different exam boards but I think for part B, the answer is £100bn as the real value should be the same as the nominal as the base rate is the first year, so inflation has no effect. GDP per head is the GDP per person, £100bn / population = GDP per capita (per head/person)
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    (Original post by Foodatastic)
    Not too sure, I suspect we do different exam boards but I think for part B, the answer is £100bn as the real value should be the same as the nominal as the base rate is the first year, so inflation has no effect. GDP per head is the GDP per person, £100bn / population = GDP per capita (per head/person)
    Thank you, im on edexcel by the way, do you agree with these answers:Name:  IMG_0100.PNG
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    (Original post by Fairy5eva)
    Thank you, im on edexcel by the way, do you agree with these answers:Name:  IMG_0100.PNG
Views: 26
Size:  307.3 KB
    The method seems correct but I'm not too sure with your calculations on B, I think it may be the new year divided by base year, however I'm not too sure. Economics not my strong point haha. I'm doing OCR so I won't be of much use.
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    (Original post by Foodatastic)
    The method seems correct but I'm not too sure with your calculations on B, I think it may be the new year divided by base year, however I'm not too sure. Economics not my strong point haha. I'm doing OCR so I won't be of much use.
    Ahah okay, thanks anyway
 
 
 
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