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    y=x^2/ax+b (a, b doesnt = 0)

    show that d^2/dx^2 = 2b^2 /(ax+b)^3

    i end up with 2a^2x^2 / (ax+b)^3

    what have i done wrong??
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    (Original post by Custardcream000)
    y=x^2/ax+b (a, b doesnt = 0)

    show that d^2/dx^2 = 2b^2 /(ax+b)^3

    i end up with 2a^2x^2 / (ax+b)^3

    what have i done wrong??
    Is that y=\dfrac{x^2}{ax+b}?
    What did you get for \frac{\text{d}y}{\text{d}x}?
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    (Original post by Kvothe the Arcane)
    Is that y=\dfrac{x^2}{ax+b}?
    What did you get for \frac{\text{d}y}{\text{d}x}?
    dy/dx = -ax^2(ax+b)^-2
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    (Original post by Custardcream000)
    dy/dx = -ax^2(ax+b)^-2
    That's incorrect. How did you get that?
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    (Original post by Custardcream000)
    dy/dx = -ax^2(ax+b)^-2
    i know what ive done wrong
 
 
 
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