You are Here: Home >< Maths

Announcements
1. Any help with this question appreciated, for part 1 am i correct in thinking that the nash equilibrium would be at 0? seeing as they choose simultaneously. For Part 2 I am completely stumped on how that would change.

Any help much appreciated
2. (Original post by Shazzy69)
Any help with this question appreciated, for part 1 am i correct in thinking that the nash equilibrium would be at 0? seeing as they choose simultaneously. For Part 2 I am completely stumped on how that would change.

Any help much appreciated

Not an expert, but from my little understanding.

Yes, 0 would be the nash equilibrium for 2 candidates. Each would get 1/2 of the votes, and any deviation from 0 would result in a loss of votes.

For three candidates, suppose two of then go for zero, then the third candidate can get almost half the votes by being slightly off zero, whilst the first two get a quarter each.

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: October 9, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### Is law a useless degree?

What do you think?

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams