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Remainder Theorem Difficult Question

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    (Original post by CIEBioloysifh)
    Write in the form
    (x-2) = (x-3) + 1
    Can you see what to do from there?
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    (Original post by CIEBioloysifh)
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    Force (x-3) into the numerator and then split the fraction. \frac{x-2}{x-3} = \frac{(x-3)+1}{x-3}
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    I think it would be helpful if you rewrite it in terms of y, where y = x-3, and then turn it back afterwards. So you get:

     (y+1) / y
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    (Original post by CIEBioloysifh)
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    \dfrac {x-2}{x-3}=\dfrac {x-3+1}{x-3}=\dfrac {x-3}{x-3}+ \dfrac {1}{x-3}=1+ \dfrac {1}{x-3}
 
 
 
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