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    I honestly don't know where I keep going wrong with this question so if someone could go through it step by step that would be great!

    A triangle has vertices (5,0),(q,0) and (10,-1) where q > 5
    Given that the area of the triangle is 4, find the value of q
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    Hi,

    Look at it logically nd work it out. Vertices mean first x co-ordinate, then y co-ordinate (best to draw diagram to visulaize (see below).

    (5, 0) means x = 5, y =0 (black cross in diag)
    (10, -1) means x = 10, y = -1 (red cross in diag) (-1 means this point (vertex in case of triangle = one corner, plural = vertices) is below the x axis.
    (q, 0) means x we don't know, y = 0 i.e. the point is on x axis where vertical value is zero(same as first vertex [point]) (assume somewhere on x axis [let us say at x = 8 1/2 simply to allow us to draw a diagram) (green cross (hypothetical = imaginary) on diag

    Then follow equation of area of triangle as in pic below - should be fairly straightforward to understand - if still not sure, send me a mess - happy to make simper.
    Name:  Maths find q triangle area.jpg
Views: 10
Size:  120.7 KB
    Thanks = hope this helps!
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    Actual triangle is purple one now that we know that q = 13
 
 
 
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