Hi, so I have a few calculation questions regarding Titration that I am finding particularly difficult. Could anyone help me with them?
1. What volume of HCl of concentration 0.25moldm-3 is needed to neutralise 5.3g of anhydrous sodium carbonate?
2. A standard solution was prepared by dissolving 2.6061g of anhydrous sodium carbonate in distilled water and making up to 250cm3. A 25.0cm3 portion of this solution was titrated against HCl. 18.7cm3 of the acid was required for neutralisation. What is the concentration of the acid?
3. A standard solution was preparing by dissolving 2.12g of anhydrous sodium carbonate in distilled water and making up to 100cm3. A 25.0cm3 portion of this solution was titrated against HCl. 33.3cm3 of the acid was required for neutralisation. What is the concentration of the acid?
I am getting pretty ridiculous answers when I try them, so any clarification would be great. Thank you!
Titration Questions Help Watch
- Thread Starter
- 11-10-2016 00:21
Kvothe the Arcane
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- 11-10-2016 04:44
1.Hydrochloric acid reacts with sodium carbonate in a 2:1 ratio. Work out the moles of sodium carbonate, use stochiomtery to work out the moles of acid and then you can use this to determine the volume needed.
2. Work out the number of moles in 250cm^3. you'll have a 10th in 25cm^3. Acid will have double the number of moles. Work out the concentration.
3. Same as no 2