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Need help with imaginary number simultaneous equation

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    Please help solve this it's bugging me a lot

    z^2 - w^2 = -2+16i
    z + iw = 4+4i


    Thanks
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    (Original post by FlyingPooMan)
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    Please help solve this it's bugging me a lot

    z^2 - w^2 = -2+16i
    z + iw = 4+4i


    Thanks
    Find w in terms of z or z in terms of w in second equation, then sub that expression into the first equation.
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    (Original post by B_9710)
    Find w in terms of z or z in terms of w in second equation, then sub that expression into the first equation.
    I have tried both and cannot end up with the right answer. I got to z^2 -4z +1 = 4zi -8i
    But I need z in the form of a+bi
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    (Original post by FlyingPooMan)
    I have tried both and cannot end up with the right answer. I got to z^2 -4z +1 = 4zi -8i
    But I need z in the form of a+bi
    You can rearrange that to get the quadratic z^2 - (4+4i)z + (1+8i) = 0
    You can now complete the square, or use the quadratic formula, to find z, where a=1, b=-(4+4i) and c=(1+8i)
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    (Original post by ejteb)
    You can rearrange that to get the quadratic z^2 - (4+4i)z + (1+8i) = 0
    You can now complete the square, or use the quadratic formula, to find z, where a=1, b=-(4+4i) and c=(1+8i)
    Thanks man!! I got the right answer it was really clever how you arranged them in quadratic form
 
 
 
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