Potassium Manganate(VII) has a concentration of 0.0200mol/dm3.
Two moles of potassium manganate(VII) react with five moles of oxalic acid crystals. Deduce the number of moles of oxalic acid crystals in 25.0 cm3 of H.
Can someone please explain the procedures for this?
Note: The question before this required you to find the number of moles of potassium manganate(VII) in a volume of 27.2, which was 0.000544 (mol). Am not sure if this helpful but it was part of the whole question.
Are you going to achieve yours?