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Find value of dy/dx (differentiation)

The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

So basically I've come as far as
dy/dx=(x+3)^3(x-5)^6(11x+1)
dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

I don't know how to solve it, can anyone help?
Original post by aziletheb
The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

So basically I've come as far as
dy/dx=(x+3)^3(x-5)^6(11x+1)
dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

I don't know how to solve it, can anyone help?


Each factor (or bracket, in other terms) can equal 0.
Original post by aziletheb
The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

So basically I've come as far as
dy/dx=(x+3)^3(x-5)^6(11x+1)
dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

I don't know how to solve it, can anyone help?



(x+3)^3=0
(x-5)^6=0
(11x+1)=0
Reply 3
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aziletheb
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Original post by RDKGames
Each factor (or bracket, in other terms) can equal 0.


Thank you so much!

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