Find value of dy/dx (differentiation)

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    The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

    So basically I've come as far as
    dy/dx=(x+3)^3(x-5)^6(11x+1)
    dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

    I don't know how to solve it, can anyone help?
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    (Original post by aziletheb)
    The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

    So basically I've come as far as
    dy/dx=(x+3)^3(x-5)^6(11x+1)
    dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

    I don't know how to solve it, can anyone help?
    Each factor (or bracket, in other terms) can equal 0.
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    (Original post by aziletheb)
    The question is: given that y=(x+3)^4(x-5)^7, find dy/dx and the values of x for which dy/dx=0

    So basically I've come as far as
    dy/dx=(x+3)^3(x-5)^6(11x+1)
    dy/dx=0, (x+3)^3(x-5)^6(11x+1)=0

    I don't know how to solve it, can anyone help?

    (x+3)^3=0
    (x-5)^6=0
    (11x+1)=0
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    (Original post by RDKGames)
    Each factor (or bracket, in other terms) can equal 0.
    Thank you so much!
 
 
 
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