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1. Calculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???
2. (Original post by Hazel99)
Calculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???
The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)
3. (Original post by charco;[url="tel:68035734")
68035734[/url]]The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)
How?
(0.05+0.02)=0.07 conc.

Do I need to get the moles?
4. (Original post by Hazel99)
How?
(0.05+0.02)=0.07 conc.

Do I need to get the moles?
You can work it out using the moles or you can use simple proportions.

15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

Now plug into the rate equation ...
5. (Original post by charco;[url="tel:68041172")
68041172[/url]]You can work it out using the moles or you can use simple proportions.

15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

Now plug into the rate equation ...
Thank you 😊

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Updated: October 15, 2016
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