Rate equations help

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Size:  499.1 KBCalculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???
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    (Original post by Hazel99)
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Size:  499.1 KBCalculate the rate of formation of C , if 15cm3 of 0.05 mol do-3 A is mixed with 20 cM3 of 0.02 moles A dm3 B ???
    The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)
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    (Original post by charco;[url="tel:68035734")
    68035734[/url]]The first thing to do is the calculate the concentrations of the components after mixing (the new volume is 35 ml)
    How?
    (0.05+0.02)=0.07 conc.

    Do I need to get the moles?
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    (Original post by Hazel99)
    How?
    (0.05+0.02)=0.07 conc.

    Do I need to get the moles?
    You can work it out using the moles or you can use simple proportions.

    15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

    The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

    The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

    Now plug into the rate equation ...
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    (Original post by charco;[url="tel:68041172")
    68041172[/url]]You can work it out using the moles or you can use simple proportions.

    15cm3 of 0.05 mol dm-3 A is mixed with 20 cm3 of 0.02 moles dm-3 B

    The new concentration of A is 0.05 x 15/35 = 0.0214 mol dm-3

    The new concentration of B is 0.02 x 20/35 = 0.0114 mol dm-3

    Now plug into the rate equation ...
    Thank you 😊
 
 
 
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