Help !! Differentiation and integration

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    How would you differentiate and integrate 8/√x ?
    Also how would you integrate 6/x^2 ?

    Thanks
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    (Original post by nisha.sri)
    How would you differentiate and integrate 8/√x ?
    Also how would you integrate 6/x^2 ?

    Thanks
    What have you got so far?

    Hint: write the expressions in the form  a x ^ n
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    (Original post by Tau)
    What have you got so far?

    Hint: write the expressions in the form  a x ^ n
    So for differentiating 8/√x i've got 8/x^3/2
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    (Original post by nisha.sri)
    How would you differentiate and integrate 8/√x ?
    Also how would you integrate 6/x^2 ?

    Thanks
    you know  \sqrt x = x^{1/2} right?
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    (Original post by 123Master321)
    you know  \sqrt[x] = x^{1/2} right?
    Yep
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    (Original post by nisha.sri)
    Yep
    are you still stuck?
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    (Original post by nisha.sri)
    So for differentiating 8/√x i've got 8/x^3/2
    Not quite. Do you know how to differentiate something like  3x^2 ? Consider what rule you're using, and apply that to this question.
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    (Original post by 123Master321)
    are you still stuck?
    Yep because for 8/√x I've got 8/X^3/2 is that right ?
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    (Original post by nisha.sri)
    How would you differentiate and integrate 8/√x ?
    Also how would you integrate 6/x^2 ?

    Thanks
    \frac{8}{\sqrt{x}} = \frac{8}{x^\frac{1}{2}} = \frac{8}{1} \times \frac{1}{x^\frac{1}{2}} = 8x^{-\frac{1}{2}} From here you can use the standard differentiation power rule. The rearranging is the same idea in the second question, then you can do the standard add 1 to the power and then divide by the new power rule.
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    (Original post by nisha.sri)
    Yep because for 8/√x I've got 8/X^3/2 is that right ?
    No, not sure how you got there, try using \frac{a}{x^n} = ax^{-n}
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    (Original post by 123Master321)
    No, not sure how you got there, try using \frac{a}{x^n} = ax^{-n}
    Oh yes i know where i went wrong thanks
    How would you do 4√x
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    sqrx=x^1/2 so 4sqrx=4x^1/2
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    Then you differentiate accordingly
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    Thanks guys i've worked it out
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    (Original post by nisha.sri)
    How would you differentiate and integrate 8/√x ?
    Also how would you integrate 6/x^2 ?

    Thanks
    Just rewrite them both using powers.
    square root x = x^1/2
    etc..

    Also, just remember: 8/√x is = 8 * 1/√x
    and dont forget the +C when integrating XD until you come to C2.
 
 
 
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