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# Domain and range c3 question Watch

1. hi, I would like some help with Q6b and Q6c please. Since x >1 surely the biggest y value can only be 4/3 so for the range I got 0<f x <4/3 but the answer is x can't be 0 why ???

Cheers
2. (Original post by coconut64)
hi, I would like some help with Q6b and Q6c please. Since x >1 surely the biggest y value can only be 4/3 so for the range I got 0<f x <4/3 but the answer is x can't be 0 why ???

Cheers
Draw the graph, as x gets larger f(x) gets smaller, it tends to 0, but the fraction cannot equal 0, so there is an asymptote at y=0
3. (Original post by NotNotBatman)
Draw the graph, as x gets larger f(x) gets smaller, it tends to 0, but the fraction cannot equal 0, so there is an asymptote at x=0
Isnt the x asymptote at x=-1/2? Since it shifts to left by 1 then halved . ... The graph I drew indicates that all the y values can only be 4/3 to 0 as x>1. Thanks
4. (Original post by coconut64)
Isnt the x asymptote at x=-1/2? Since it shifts to left by 1 then halved . ... The graph I drew indicates that all the y values can only be 4/3 to 0 as x>1. Thanks
Sorry, I meant at y=0 , and the range of y values is less than 4/3 and greater than 0, so you've got it right.
5. to draw y = 4/ { 2x + 1 }

i) draw y = 1/x : you should know what this looks like.

ii) move it 1 unit left

iii) squash horizontally by a factor of 2

iv) stretch vertically by a factor of 4

*

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Updated: October 16, 2016
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