Join TSR now and get all your revision questions answeredSign up now

Limiting and excess reagent Watch

    • Thread Starter

    What is the maximum mass of ammonia that can be recovered from 2.00 tonnes(2000000g) of ammonium chloride and 0.500 tonnes of calcium oxide?
    balanced eq- 2NH4Cl + CaO --> CaCl2 + H20+ 2NH3
    • Official TSR Representative

    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

    Just quoting in Danny Dorito so she can move the thread if needed :wizard:
    (Original post by Danny Dorito)

    2NH4Cl + CaO --> CaCl2 + H20+ 2NH3

    First work out mass no of NH4Cl: N = 14
    H4 = 4
    Cl = 35.5
    TOTAL = 53.5
    2NH4Cl = 107

    Mass no of CaO Ca = 40
    O = 16
    TOTAL = 56

    So 107 g of NH4CL would react with 56g of CaO i.e. tehere is a bit less than double mass of NH4Cl compared to CaO

    We have 2 tonnes of NH4CL and 0.5 tonnes of CaO; here NH4CL is 4 times as much as CaO, so NH4Cl is in excess. We use the mass of CaO = 0.5 tonnes to calculate amount of NH3 gas recoverable, because CaO is the limiting factor.

    Mass No of NH3 = 14 + 3 = 17But 2 moles are produced = 34 g

    56 g CaO gives 34 g NH3

    So 0.5 tonnes of Cao gives 500 kg/56 X 34 = 303.6 kg of ammonia
Is GoT overrated?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.