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    • Thread Starter


    I'm having a bit of trouble with my maths coursework. It involves using 3 different methods in order to find a root of an equation, put simply.

    One of those methods is fixed point iteration.

    In the guide that I have in front of me, it says that the equation f(x)=0 is rearranged into the form x=g(x). I am not sure I understand what g(x) is. Could someone please check that my understanding is correct.

    If I have the equation y=x^2
    this can be written f(x)=x^2
    so therefore g(x)=sqrt(y)

    where sqrt is square root, sorry didn't know how to do the symbol and not sure what the standard computing representation is of it.

    Could some one please just check that my understanding is correct, and if not, maybe point me in the right direction?

    cheers guys


    What is f(x) = 0 about?

    My understanding is that g(y) is the inverse function of f(x), if f(x)=y then g(y)=x.

    Although, I think one can only have one answer to an inverse function and therefore you have to chose either  g(y) = \sqrt{y} or  g(y) = - \sqrt{y}

    Also fixed point is all about finding a point where f(x) = x not f(x) = 0 (if not x equals zero that is).

    I might've misunderstood you, though. Hope it helped, although I might not be the best person to explain this to you as I am just reading up on "Inverse functions" myself.

    Here's an extract from my coursework (don't you dare plagiarise - I think it would be pretty obvious if you did!). I think it explains the method quite well. Hope that helps.
    Attached Files
  1. File Type: doc Rearrangement Method.doc (125.0 KB, 1832 views)
    • Thread Starter

    cheers mate, yer that helps alot! Course I wont plagerise, but ur cw is on the net now for any1 to see, so I have saved it so if you can, delete it so it limits the no. of people that have access to it!

    thanx again mate, really do appreciate that

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Updated: August 15, 2007

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