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Probability Help ( 2 Fair dice) Watch

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    Can someone explain why the probability of rolling 2 fair dice and getting a Probability of getting total 10 and getting for on green is 3/36?
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    (Original post by TheAdviser101)
    Can someone explain why the probability of rolling 2 fair dice and getting a Probability of getting total 10 and getting for on green is 3/36?
    Where does the green come in to all of this? But imagine it like this. There are trivially two ways of making 10 and they are  6+4=10 \enspace \text{and} \enspace 5+5=10 .

    Now on a fair dice the probability of getting any one number is \frac{1}{6}.
    10 can be made in the following ways:
    6+4=10
    4+6=10
    5+5=10
    Each way has probability \frac{1}{6}\times\frac{1}{6}= \frac{1}{36}
    And as there are three potential ways of doing this the total probability of getting a 10 is  \frac{3}{36}
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    (Original post by Cryptokyo)
    Where does the green come in to all of this? But imagine it like this. There are trivially two ways of making 10 and they are  6+4=10 \enspace \text{and} \enspace 5+5=10 .

    Now on a fair dice the probability of getting any one number is \frac{1}{6}.
    10 can be made in the following ways:
    6+4=10
    4+6=10
    5+5=10
    Each way has probability \frac{1}{6}\times\frac{1}{6}= \frac{1}{36}
    And as there are three potetial ways of doing this the total probability of getting a 10 is  \frac{3}{36}
    There are 2 dices green and red. Sorry, its my fault I haven't worded the question out properly. I am confused about the part in the screenshot below. I don't see how the probability becomes 3/36
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    [img]file:///C:/Users/Admin/AppData/Local/Temp/msohtmlclip1/01/clip_image002.jpg[/img]
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    (Original post by TheAdviser101)
    There are 2 dices green and red. Sorry, its my fault I haven't worded the question out properly. I am confused about the part in the screenshot below. I don't see how the probability becomes 3/36
    Name:  Picture1.png
Views: 15
Size:  141.2 KB
    [img]file:///C:/Users/Admin/AppData/Local/Temp/msohtmlclip1/01/clip_image002.jpg[/img]
    I believe their answer is incorrect as the condition is P(total 10 and 4 on green) would yield a probability of \frac{1}{6}\times\frac{1}{6}= \frac{1}{36} as the events are independent. And 6 is the only number that can give a total of ten. This would imply the equation should be:
    \frac{\frac{1}{6}\times\frac{1}{  6}}{\frac{1}{6}}=\frac{1}{6}

    I believe it should be \frac{1}{36} and not \frac{3}{36} in the equation.

    Could you send me a link to the document so I can double check this though.
 
 
 
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