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# stuck on a c3 question Watch

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1. http://www.examsolutions.net/exampap...-c3-june-2006/

For question 4c for this paper where you are asked to find the rate of the decreasing of the temperature, how do you know you need to differentiate it?

Thanks
2. (Original post by coconut64)
http://www.examsolutions.net/exampap...-c3-june-2006/

For question 4c for this paper where you are asked to find the rate of the decreasing of the temperature, how do you know you need to differentiate it?

Thanks
It's asking you to find the rate.

When you're differentiating, you're getting the gradient function - which is essentially a fancy way of saying you're finding the rate at which something decreases or increases.
3. (Original post by coconut64)
http://www.examsolutions.net/exampap...-c3-june-2006/

For question 4c for this paper where you are asked to find the rate of the decreasing of the temperature, how do you know you need to differentiate it?

Thanks
Because a derivative describes the rate of change for whatever you differentiate.
4. (Original post by coconut64)
http://www.examsolutions.net/exampap...-c3-june-2006/

For question 4c for this paper where you are asked to find the rate of the decreasing of the temperature, how do you know you need to differentiate it?

Thanks
The derivative is the rate of change of T with respect to t. So to find the rate at which the temperature is decreasing, find dT/dt, which represents the rate at which it is decreasing, then you can find it at any value of t.
5. (Original post by jamestg)
It's asking you to find the rate.

When you're differentiating, you're getting the gradient function - which is essentially a fancy way of saying you're finding the rate at which something decreases or increases.
thanks
6. thanks for the help, I get it now!
7. (Original post by RDKGames)
Because a differential describes the rate of change for whatever you differentiate.
Derivative
8. (Original post by B_9710)
Derivative
Aw damn, now I look silly.
9. (Original post by RDKGames)
Aw damn, now I look silly.
https://youtu.be/t93u0qg5q_M

Updated: October 18, 2016
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