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Chemistry Titration Maths question

Hey, I was wondering if anyone can help me with this:

25cm^3 of 0.2mol dm^-3 NaOH reacts with 11.2cm^3 of H2SO4. Calculate the concentration of the sulphuric acid.

Thank you x
Reply 1
Avatar for 1+5t
1+5t
16
Nah02-7/44^^(46)= 2-O.2233M HCL NaOH/3mns

Hope this helps
Reply 2
Avatar for B_9710
B_9710
18
Calculate the number of moles of NaOH which is 25×10−3 25\times 10^{-3} and we know that
Unparseable latex formula:

[\text{OH}^-] =[\text{H}^+} ]

so [H+]=25×10−3 [\text{H}^+]=25\times 10^{-3} BUT [H+]=[H2SO4] [\text{H}^+ ]=[\text{H}_2\text{SO}_4 ] since 1 mole of sulphuric acid releases 2 H+.
(edited 7 years ago)

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