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Help with tangent problem

b) At the point R, the tangent to f(x) = 1/(4x) is parrallel to the line x+4y+12=0.

Find the two possible coordinates of R.

I found the equation of the tangent to f(x) = 1/(4x), x+16y-4=0, can someone tell me what I need to do now?
Reply 1
The parrallel line has gradient 14-\frac{1}{4}. From there, you have to derive f(x)f(x) and find the x-coordinates for which the slope of the tangent line to the curve is equal to 14-\frac{1}{4}.
Reply 2
Original post by ℓove
b) At the point R, the tangent to f(x) = 1/(4x) is parrallel to the line x+4y+12=0.

Find the two possible coordinates of R.

I found the equation of the tangent to f(x) = 1/(4x), x+16y-4=0, can someone tell me what I need to do now?


The question is trying to trick you by putting the equation of a line in there. The question basically reads find the coordinates of the points on the curve y=14x y=\frac{1}{4x} where dy/dx=1/4 dy/dx=-1/4 .

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