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    Hi I have a question I'm stuck with, any help would be appreciated.

    Two hooks, A and B, are fixed to the ceiling. The distance AB is 2.5 m.

    a) A particle, C, of mass 3kg is suspended from A and B by two light, inextensible strings. AC is 2 m and BC is 1.3 m. Calculate the tension in the strings,

    b) The two strings are now replaced by a single string of length 3.3 m, which is threaded through a smooth ring attached to the particle. A horizontal force, P N, is applied to the particle so that it rests in the same position as before. Calculate the value of P and tension in the string.

    I've done the first part. I used the cosine rule and then equated the horizontal and vertical forces. However I'm obtaining the wrong answer for b and can't spot my mistake. I've attached my diagram.

    Thank you in advance.
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    Without getting stuck in to all of the technical details - is it because you only have one T in your diagram? Should there not be the same T, pointing along the directions of both parts of the string from the ring?
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    (Original post by Pangol)
    Without getting stuck in to all of the technical details - is it because you only have one T in your diagram? Should there not be the same T, pointing along the directions of both parts of the string from the ring?
    Ok thank you, I understand that and will give it a go.
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    (Original post by tommy_lees)
    Ok thank you, I understand that and will give it a go.
    Thank you. With the two tension strings it works. Thanks for your help.
 
 
 
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