Two arials are 2.5m apart and both are receiving the radiowaves signal with frequency of 125Hz. The phase difference between two signal is 114 degrees.
Calculate the path difference?
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Last edited by acidmissk; 26-10-2016 at 15:30.
- 25-10-2016 18:06
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- 27-10-2016 19:20
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- 24-11-2016 09:19
125Hz is a very long wavelength. Long wave is 1500 metres which equates to a frequency of 2 X 10^5 Hz.
125 Hz = 3 X 10^8/125 = 2.4 X 10^6 m =2400 Km.
Also, I can't see where the 2.5m comes in? Have you posted the whole question?
The phase difference suggests a path difference is 114/360 ths of a wavelength. (It could be any number of wavelengths plus 114/360ths of one but that is another matter).
Anyway the wavelength is c/f = 3 X 10^8 / 125 = 2.4 X 10^6 metres
Then you need 114/360 ths of that to get the path difference. = 7.6 X 10^5 m = 760 km which does not seem sensible.