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    Two arials are 2.5m apart and both are receiving the radiowaves signal with frequency of 125Hz. The phase difference between two signal is 114 degrees.
    Calculate the path difference?
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.


    Just quoting in Danny Dorito so she can move the thread if needed :wizard:
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    125Hz is a very long wavelength. Long wave is 1500 metres which equates to a frequency of 2 X 10^5 Hz.

    125 Hz = 3 X 10^8/125 = 2.4 X 10^6 m =2400 Km.

    Also, I can't see where the 2.5m comes in? Have you posted the whole question?

    The phase difference suggests a path difference is 114/360 ths of a wavelength. (It could be any number of wavelengths plus 114/360ths of one but that is another matter).

    Anyway the wavelength is c/f = 3 X 10^8 / 125 = 2.4 X 10^6 metres

    Then you need 114/360 ths of that to get the path difference. = 7.6 X 10^5 m = 760 km which does not seem sensible.
 
 
 
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