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# waves a level questions (need help) watch

1. Two arials are 2.5m apart and both are receiving the radiowaves signal with frequency of 125Hz. The phase difference between two signal is 114 degrees.
Calculate the path difference?
2. Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

Just quoting in Danny Dorito so she can move the thread if needed
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(Original post by Danny Dorito)
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3. 125Hz is a very long wavelength. Long wave is 1500 metres which equates to a frequency of 2 X 10^5 Hz.

125 Hz = 3 X 10^8/125 = 2.4 X 10^6 m =2400 Km.

Also, I can't see where the 2.5m comes in? Have you posted the whole question?

The phase difference suggests a path difference is 114/360 ths of a wavelength. (It could be any number of wavelengths plus 114/360ths of one but that is another matter).

Anyway the wavelength is c/f = 3 X 10^8 / 125 = 2.4 X 10^6 metres

Then you need 114/360 ths of that to get the path difference. = 7.6 X 10^5 m = 760 km which does not seem sensible.

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