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# Simultaneous C1 maths watch

1. Hi guys,
I'm having trouble to solve this simultaneous. y + 4x +1=0 and y^2 +5x^2 -2x = 0
Ive got up to 21x^2 +6x+1 =0
How would I factorise it ??
Thanks

Ooops ik blind I can't see properly it was a + but I thought it was a -
2. you could either use the equation or try to complete the square
3. (Original post by nisha.sri)
Hi guys,
I'm having trouble to solve this simultaneous. y + 4x +1=0 and y^2 +5x^2 -2x = 0
Ive got up to 21x^2 +6x+1 =0
How would I factorise it ??
Thanks
Have you heard of the ac method?https://www.youtube.com/watch?v=RoeNm4LF9YQ

Hope it helps
4. (Original post by nisha.sri)
Hi guys,
I'm having trouble to solve this simultaneous. y + 4x +1=0 and y^2 +5x^2 -2x = 0
Ive got up to 21x^2 +6x+1 =0
How would I factorise it ??
Thanks
The quadratic is wrong as there are no real solutions. Try solving the simultaneous equation again. Make y or x the subject of the first equation and substitute it into the other equation.
5. (Original post by CrystalSalvatore)
you could either use the equation or try to complete the square
Ive tried the formula but all I'm getting is a lot of fractions.
6. (Original post by nisha.sri)
Ive tried the formula but all I'm getting is a lot of fractions.
That's because the quadratic is incorrect, start over.
7. (Original post by NotNotBatman)
That's because the quadratic is incorrect, start over.
8. (Original post by nisha.sri)
How are you doing it, could you show some steps?
9. (Original post by NotNotBatman)
How are you doing it, could you show some steps?
Sorry it's a bit messy
10. (Original post by nisha.sri)

Sorry it's a bit messy
Are you sure you've written the question down correctly, because there are no real solutions to the quadratic. Post the original question please.
11. (Original post by NotNotBatman)
Are you sure you've written the question down correctly, because there are no real solutions to the quadratic. Post the original question please.
Ive posted it above
12. (Original post by nisha.sri)
Ive posted it above
Is that a +2x ? If it is then it can be solved.
13. that's +2x not -2x, mate.
14. (Original post by NotNotBatman)
Is that a +2x ? If it is then it can be solved.
(Original post by AspiringUnderdog)
that's +2x not -2x, mate.
Omg that's so annoying !!!! But it's LOOKs like a - anyways thank you

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