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# Simple trignometric ratios.. watch

1. How would u solve this problem

if sinx=0.6 and x is acute, what are cos x and tan x

Completely forgotten how to do this stuff....
2. x = sin^-1(0.6)
Then just do cos(x) and tan(x) in intervals 0<x<90 - which in the case of cos(x) and tan(x) will just give on value - the answer you get on your calculator.
3. (Original post by marzipan100)
How would u solve this problem

if sinx=0.6 and x is acute, what are cos x and tan x

Completely forgotten how to do this stuff....
Convert into a fraction, sketch a right angled triangle with angle x that satisfies the ratio.

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