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    How would u solve this problem

    if sinx=0.6 and x is acute, what are cos x and tan x

    Completely forgotten how to do this stuff....
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    x = sin^-1(0.6)
    Then just do cos(x) and tan(x) in intervals 0<x<90 - which in the case of cos(x) and tan(x) will just give on value - the answer you get on your calculator.
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    (Original post by marzipan100)
    How would u solve this problem

    if sinx=0.6 and x is acute, what are cos x and tan x

    Completely forgotten how to do this stuff....
    Convert into a fraction, sketch a right angled triangle with angle x that satisfies the ratio.
 
 
 
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