can someone plz help me on this question.
what is the order of the magnitude of the force of attraction between a proton and an electron separated by a distance of 10^-10m
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- Thread Starter
- 27-10-2016 14:44
- Official Rep
- 29-10-2016 16:10
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Just quoting in Danny Dorito so she can move the thread if needed
Spoiler:Show(Original post by Danny Dorito)
- 29-10-2016 16:40
I'm not sure what is meant by "order of the magnitude of the force" but the magnitude of the electrostatic force between two bodies is found using Coulombs Law:
F = electrostatic force between two bodies in Newtons/N
k = Coulombs constant (Use the k value if you're given it)
is the charge size of one particle
is the charge size of the second particle
r = the distance apart in metres/m
The charge of a proton is +1e and the charge of an electron is -1e
So effectively they are equal sized charges so and are equal therefore
I'm sorry if this didn't answer your question (because of the wording of the question slightly confused me)Last edited by ManLike007; 29-10-2016 at 16:41.
- 29-10-2016 16:44
ooo quick addition to the above answer:
order of magnitude means what power of 10 it is
e.g. 3.0x10^8 has order of magnitude 8
My physics teacher is a recent graduate and jeez does he say this term a LOT.