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    can someone plz help me on this question.

    what is the order of the magnitude of the force of attraction between a proton and an electron separated by a distance of 10^-10m
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.


    Just quoting in Danny Dorito so she can move the thread if needed :wizard:
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    I'm not sure what is meant by "order of the magnitude of the force" but the magnitude of the electrostatic force between two bodies is found using Coulombs Law:

    F = k \frac{Q_1 Q_2}{r^2}

    Where:
    F = electrostatic force between two bodies in Newtons/N
    k = Coulombs constant (Use the k value if you're given it)
    Q_1 is the charge size of one particle
    Q_2 is the charge size of the second particle
    r = the distance apart in metres/m

    The charge of a proton is +1e and the charge of an electron is -1e

    So effectively they are equal sized charges so Q_1 and Q_2 are equal therefore

    F = k \frac{Q^2}{r^2}

    I'm sorry if this didn't answer your question (because of the wording of the question slightly confused me)
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    ooo quick addition to the above answer:
    order of magnitude means what power of 10 it is
    e.g. 3.0x10^8 has order of magnitude 8

    My physics teacher is a recent graduate and jeez does he say this term a LOT.
 
 
 
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