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    can someone plz help me on this question.

    what is the order of the magnitude of the force of attraction between a proton and an electron separated by a distance of 10^-10m
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    Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.

    Just quoting in Danny Dorito so she can move the thread if needed :wizard:
    (Original post by Danny Dorito)

    I'm not sure what is meant by "order of the magnitude of the force" but the magnitude of the electrostatic force between two bodies is found using Coulombs Law:

    F = k \frac{Q_1 Q_2}{r^2}

    F = electrostatic force between two bodies in Newtons/N
    k = Coulombs constant (Use the k value if you're given it)
    Q_1 is the charge size of one particle
    Q_2 is the charge size of the second particle
    r = the distance apart in metres/m

    The charge of a proton is +1e and the charge of an electron is -1e

    So effectively they are equal sized charges so Q_1 and Q_2 are equal therefore

    F = k \frac{Q^2}{r^2}

    I'm sorry if this didn't answer your question (because of the wording of the question slightly confused me)

    ooo quick addition to the above answer:
    order of magnitude means what power of 10 it is
    e.g. 3.0x10^8 has order of magnitude 8

    My physics teacher is a recent graduate and jeez does he say this term a LOT.
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