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# Titration questions - urgent help!! watch

1. 1) What amount (in moles) of solute is needed to make 50cm^3 of 1.0M solution?

I know this question sounds really simple but I keep overthinking it and I don't know the units or equation to use...
2. The equation you need is concentration = number of mols devided by volume.
c= 1moldm^-3
n=
v=50cm^3
were looking for n an amount so we would multiply the two. However me must convert the cm^3 do dm^3 in the volume before we can do this. To do this we devide my 1000. 1moldm^-3*50*10^-3dm^3 = 0.05 mols
3. (Original post by lowkey-loki)
The equation you need is concentration = number of mols devided by volume.
c= 1moldm^-3
n=
v=50cm^3
were looking for n an amount so we would multiply the two. However me must convert the cm^3 do dm^3 in the volume before we can do this. To do this we devide my 1000. 1moldm^-3*50*10^-3dm^3 = 0.05 mols
Okay, thank you so so much!!

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