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    I have the curve. I anticipate that there will be a kink/sharp twist in said curve.With the boldened information being the most relevant - how would I solve this integral.So far I have




    ds=||AB→||dtds=||AB→||dt



    [Although I express doubt and skepticism whether this is right.]Thank you for any help/assistance given.
    This is my working out so far. i would appreciate if anyone caould confirm whether I am correct, or assist me please.
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    I'm assuming the curve is supposed to be two line segments. So split the integral up into the two segments (and just add the results for each segment at the end).

    For a line from a to b you simply want to parameterize as (x, y, z) = a + t(b - a) (with t going from 0 to 1). So you'll have simple linear functions for x, y, z as functions of t. (E.g. for your segment from (1, 0, 1) to (0, 1, 0) you'd have x = 1 - t, and then you replace dx by \dfrac{dx}{dt} dt = -dt). You'll end up with a simple integral of form

    \displaystyle \int_0^1 \text{"stuff that's a function of t"} \, dt for each segment.

    Edit: I haven't really addressed what you've tried to do, because all the stuff with cos and sin seems to be completely irrelevant and I'm not sure what you're actually trying to do.
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    (Original post by DFranklin)
    I'm assuming the curve is supposed to be two line segments. So split the integral up into the two segments (and just add the results for each segment at the end).

    For a line from a to b you simply want to parameterize as (x, y, z) = a + t(b - a) (with t going from 0 to 1). So you'll have simple linear functions for x, y, z as functions of t. (E.g. for your segment from (1, 0, 1) to (0, 1, 0) you'd have x = 1 - t, and then you replace dx by \dfrac{dx}{dt} dt = -dt). You'll end up with a simple integral of form

    \displaystyle \int_0^1 \text{"stuff that's a function of t"} \, dt for each segment.

    Edit: I haven't really addressed what you've tried to do, because all the stuff with cos and sin seems to be completely irrelevant and I'm not sure what you're actually trying to do.

    Thank you I changed the parameter to make it in terms of t and I got 1/3 and 34/3 for the two segments.
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    thanks for this ^^^

    I thought you left this forum

    Your papers got me from a U to an A in M1. Thank you
 
 
 
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