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    Could anyone help me on these 2 questions please?

    I'm completely lost

    1)calculate the mass of nitric acid required to react completely with 90g of copper

    3Cu + 8HNO3 producing 3Cu(NO3)2 +2NO +4H2O

    2) What mass of iron is formed when one kilogram (1000g) of irone ore, Fe203 , reacts in excess carbon monoxide?

    FE203 + 3CO producing 2FE +3CO2

    Thanks! <3
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    (Original post by Wisdom2)
    Could anyone help me on these 2 questions please?

    I'm completely lost

    1)calculate the mass of nitric acid required to react completely with 90g of copper

    3Cu + 8HNO3 producing 3Cu(NO3)2 +2NO +4H2O

    2) What mass of iron is formed when one kilogram (1000g) of irone ore, Fe203 , reacts in excess carbon monoxide?

    FE203 + 3CO producing 2FE +3CO2

    Thanks! <3
    1) Work out the moles of copper using the equation: mass= molecular mass x moles
    Then use the molar ratio between copper and nitric acid, which is 3:8. Re-use the equation to find mass.

    2)Again, work out the moles of iron ore with the above equation. Then use the molar relationship between iron ore and iron which is 1:2. Re-use equation to find mass.
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    (Original post by Ze Witcher)
    1) Work out the moles of copper using the equation: mass= molecular mass x moles
    Then use the molar ratio between copper and nitric acid, which is 3:8. Re-use the equation to find mass.

    2)Again, work out the moles of iron ore with the above equation. Then use the molar relationship between iron ore and iron which is 1:2. Re-use equation to find mass.
    Aw, will do! Thanks for replying, such a nice person!
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    (Original post by Wisdom2)
    Aw, will do! Thanks for replying, such a nice person!
    No problemo
 
 
 
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