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    Can someone help me with this question please?


    Sodium hydroxide is often sold as a concentrated solution containing 12.0 moldm^(-3) of sodium hydroxide.

    Calculate the volume of water that should be added to 10.0 cm^(3) of a 12.0 moldm^(-3) solution of sodium hydroxide to make a 0.250 moldm^(-3) solution.
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    Calculate no. of moles which is concentration x volume, therefore 12.0x10 = 120 moles

    To calculate total volume, divide no. of moles by concentration of new solution, so 120/0.250= 480 cm^3

    As the question asks to calculate the volume needed to be added to 10.0 cm^3, 480-10=470 cm^3 of water needs to be added
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    (Original post by aa98)
    Calculate no. of moles which is concentration x volume, therefore 12.0x10 = 120 moles

    To calculate total volume, divide no. of moles by concentration of new solution, so 120/0.250= 480 cm^3

    As the question asks to calculate the volume needed to be added to 10.0 cm^3, 480-10=470 cm^3 of water needs to be added


    Thank you soooooo much
 
 
 
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