So this stupid question is actually making me cry.
Find the PH of the following:
Using [ethanoi acid] =0.10moldm-3
[sodium ethanoate] =0.2moldm-3
[ka of ethanoic acid = 1.7x10^-5]
i may be would have done it if the conc of sodium ethanoate wasn't bigger than the ethanoic acid !
Turn on thread page Beta
CHEMISTRY QUESTION !! BUFFERS!! Pls help - stuck for four hours! watch
- Thread Starter
- 29-10-2016 10:24
- Official Rep
- 31-10-2016 10:40
Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.
Just quoting in Danny Dorito so she can move the thread if needed
Spoiler:Show(Original post by Danny Dorito)