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    Theres the question im struggling with^^
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    formula for area of triangle is 1/2 absinC
    (or in your case 1/2(AB)(BC)sinC)
    since BC is double AB let AB=2x and BC=x
    substitute from there. do note you already have the area so you'll have to re arrange.

    I would do it myself but it's better to help and not to just do. Do post your answer though and ill compare it with mine
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    (Original post by Toasticide)
    formula for area of triangle is 1/2 absinC
    (or in your case 1/2(AB)(BC)sinC)
    since BC is double AB let AB=2x and BC=x
    substitute from there. do note you already have the area so you'll have to re arrange.

    I would do it myself but it's better to help and not to just do. Do post your answer though and ill compare it with mine
    Thanks a lot for explaining it to me!, I knew the answer(from the markscheme), but I didn't understand how to work it out. I didn't realize that the length AB and BC could be substituted as ab in the formula, otherwise it would of been easier.

    The correct answer 4 root 5
 
 
 
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