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# Struggling on this C1 question watch

1. I can't figure out what to do here:
Given that f(x)=1/x , x is not equal to 0
(a) Sketch the graph of y = f (x) + 3 and state the equations of the asymptotes
(b) Find the coordinates of the point where y = f (x) + 3 crosses a coordinate axis
2. (Original post by Alpha°)
I can't figure out what to do here:
Given that f(x)=1/x , x is not equal to 0
(a) Sketch the graph of y = f (x) + 3 and state the equations of the asymptotes
(b) Find the coordinates of the point where y = f (x) + 3 crosses a coordinate axis
I hope someone knows how to do this because i would also like to know how this is done.
3. (Original post by Alpha°)
I can't figure out what to do here:
Given that f(x)=1/x , x is not equal to 0
(a) Sketch the graph of y = f (x) + 3 and state the equations of the asymptotes
(b) Find the coordinates of the point where y = f (x) + 3 crosses a coordinate axis
Watch the videos under graph transformations and asymptotes

http://www.examsolutions.net/a-level.../c1-tutorials/

then revisit this question
4. Basically it's just 1/x moved up by 3. This means the asymptote at x=0 doesn't change and the asymptote at y=0 moves up by 3 to y=3.

Then for B from the sketch you will see it crosses the x axis once so solve for x in 0=(1/x) + 3 since y is 0 when it crosses x axis
5. (Original post by Alpha°)
I can't figure out what to do here:
Given that f(x)=1/x , x is not equal to 0
(a) Sketch the graph of y = f (x) + 3 and state the equations of the asymptotes
(b) Find the coordinates of the point where y = f (x) + 3 crosses a coordinate axis
(Original post by Vinni0001)
I hope someone knows how to do this because i would also like to know how this is done.
Find out what the graph of 1/x looks like. (NOTE: you can either substitute values into it to calculate coordinates, or you can cheat and use the internet or a graphical calculator.) Transform is by the column vector
0
3

NOTE: there should be an asymptote
6. (Original post by metrize)
Basically it's just 1/x moved up by 3. This means the asymptote at x=0 doesn't change and the asymptote at y=0 moves up by 3 to y=3.

Then for B from the sketch you will see it crosses the x axis once so solve for x in 0=(1/x) + 3 since y is 0 when it crosses x axis
thanks
7. (Original post by 04MR17)
Find out what the graph of 1/x looks like. (NOTE: you can either substitute values into it to calculate coordinates, or you can cheat and use the internet or a graphical calculator.) Transform is by the column vector
0
3

NOTE: there should be an asymptote
(Original post by metrize)
Basically it's just 1/x moved up by 3. This means the asymptote at x=0 doesn't change and the asymptote at y=0 moves up by 3 to y=3.

Then for B from the sketch you will see it crosses the x axis once so solve for x in 0=(1/x) + 3 since y is 0 when it crosses x axis
(Original post by Naruke)
Watch the videos under graph transformations and asymptotes

http://www.examsolutions.net/a-level.../c1-tutorials/

then revisit this question
(Original post by Alpha°)
thanks
Yh, thanks guys i understand now

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