Turn on thread page Beta
    • Thread Starter
    Offline

    12
    ReputationRep:
    If f(x) is a real valued function such that 2f(x) + 3f(−x) = 15 − 4x, for every x ∈ R, what is the value of f(2)?

    How do you solve this?
    Offline

    15
    ReputationRep:
    Stick x=2 and x=-2 in, try juggling that around?
    2f(2) + 3f(-2) = 7
    2f(-2) + 3f(2)= 23
    then solve simultaneously
    • Thread Starter
    Offline

    12
    ReputationRep:
    If you could also help me with this functions question please. Its a function inside a function which confuses me
    Name:  fx.png
Views: 15
Size:  10.3 KB



    (Original post by an_atheist)
    Stick x=2 and x=-2 in, try juggling that around?
    2f(2) + 3f(-2) = 7
    2f(-2) + 3f(2)= 23
    then solve simultaneously
    Offline

    15
    ReputationRep:
    m=1 n=1, sub into the third function set to return f(0,f(1,0)). F(1,0) = f(0,1) = 2
    F(0,2) = 3, B
    That's the answer I get
    • Thread Starter
    Offline

    12
    ReputationRep:
    (Original post by an_atheist)
    m=1 n=1, sub into the third function set to return f(0,f(1,0)). F(1,0) = f(0,1) = 2
    F(0,2) = 3, B
    That's the answer I get
    How do you solve the
    f(0,f(1,0))
    • Community Assistant
    Offline

    20
    ReputationRep:
    Community Assistant
    (Original post by Carman3)
    How do you solve the
    f(0,f(1,0))
    Firstly evaluate f(1,0)
    • Thread Starter
    Offline

    12
    ReputationRep:
    (Original post by RDKGames)
    Firstly evaluate f(1,0)
    I got f(0,1) for that then what i do do i run it back through the function if so what line do i use
    • Community Assistant
    Offline

    20
    ReputationRep:
    Community Assistant
    (Original post by Carman3)
    I got f(0,1) for that then what i do do i run it back through the function if so what line do i use
    Yeah so what is f(0,1)?? Check the conditions in the piecewise function to determine what happens.

    It is easier to lay it out step by step:

    f(1,1)=f(0,f(1,0))=f(0,f(0,1))=.  ..
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: October 30, 2016
The home of Results and Clearing

3,010

people online now

1,567,000

students helped last year

University open days

  1. Bournemouth University
    Clearing Open Day Undergraduate
    Wed, 22 Aug '18
  2. University of Buckingham
    Postgraduate Open Evening Postgraduate
    Thu, 23 Aug '18
  3. University of Glasgow
    All Subjects Undergraduate
    Tue, 28 Aug '18
Poll
How are you feeling about GCSE results day?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.