You are Here: Home

# boltzmann question watch

1. the boltzmann equation is given by Ni/N0 = exp (-Ei/RT) where Ni is the number of atoms or molecules in a state with energy Ei and N0 is the number of atoms or molecules in the lowest energy state with zero energy. At 1000k, what % of the molecules are in a state i with an energy of 5KJmol-1 assuming both levels have the same degeneracy

anyone know how to do this?
2. You already have the equation required.

You know , and . Just make sure you have everything with the right units and that gives you the ratio of atoms/molecules in state i to state 0.

To find out the proportion of total molecules in state i you need more information.
3. (Original post by alow)
You already have the equation required.

You know , and . Just make sure you have everything with the right units and that gives you the ratio of atoms/molecules in state i to state 0.

To find out the proportion of total molecules in state i you need more information.
I just get an error when i do exp (5000/1000 x 138065x10^-23)
4. (Original post by jacksonmeg)
I just get an error when i do exp (5000/1000 x 138065x10^-23)
You forgot the - sign, and check your units.
5. (Original post by alow)
You forgot the - sign, and check your units.
now i got 0
6. (Original post by jacksonmeg)
now i got 0
7. (Original post by alow)
i converted energy to j mol-1, temperature in kelvin and boltzmann constant in J K-1 i dont see whats wrong
8. (Original post by jacksonmeg)
i converted energy to j mol-1, temperature in kelvin and boltzmann constant in J K-1 i dont see whats wrong
You need to cancel the mol.
9. (Original post by alow)
You need to cancel the mol.
so just put 6.022x10^-23 on the denominator
10. (Original post by jacksonmeg)
so just put 6.022x10^-23 on the denominator
You want Avogadros number on the numerator.
11. (Original post by alow)
You want Avogadros number on the numerator.
then i get 0 again
12. (Original post by jacksonmeg)
then i get 0 again
Yeah easier to use .

13. Is this like university level physics because I've not understood the last 2 threads you've put up.

Posted from TSR Mobile
14. (Original post by RossB1702)
Is this like university level physics because I've not understood the last 2 threads you've put up.

Posted from TSR Mobile
It's probably second year Chemistry.

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: October 30, 2016
The home of Results and Clearing

### 2,218

people online now

### 1,567,000

students helped last year
Today on TSR

### University open days

1. Sheffield Hallam University
Tue, 21 Aug '18
2. Bournemouth University
Wed, 22 Aug '18
3. University of Buckingham