I need help with this question:
How many grams of the substance would you need to make the following solution: 2L of 6M HCl
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- Thread Starter
- 30-10-2016 12:51
- 02-11-2016 19:40
First, remember that 6M is 6moldm3, and 2L is 2dm3.
Using n=cv, the number of moles needed is 2dm3 x 6moldm-3 = 12mol.
Using a periodic table, you know the molar mass of H is 1, and Cl is 35.5, so the molar mass of HCl is 1 + 35.5 = 36.5. This means that 1mol of the substance has mass 36.5g.
Multiply this by 12 to get 36.5gmol-1 x 12mol = 438g.