# Question 2.2 - Power factor and Capacitor to correct it. watch

1. An AC load takes 5 kW of power from a supply 240V at 50 Hz. The current is 30 A. Determine the power factor and the value and rating of a capacitor needed in series to correct it....

So far...

kVA = 240V * 30A = 7.2kW
PF = 5kW/7.2kW = 0.694

Z = V/I = 240/30 = 8Ohms

Z = sqrt(R2 + (XL – XC2))

XC = 1/(2piFC) so C = 1/(2piFXC)

Have no idea how to transpose Z or even if that's the right way to do it.

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