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    Right so here's the question:

    1) The “Humphreys series” is a less frequently discussed series in the atomic emission spectrum of hydrogen. The lowest energy line of the series is at 12371.9 nm and the sixth line of the series lies at 4376.5 nm. RH= 109677.8 cm-1
    i) Find the principal quantum number of the upper and lower levels (n1,n2) for both of the above transitions.

    I know the formula is v=-RH(1/n2^2-1/n1^2) but I don't know what n1 or n2 are so I'm left with 2 unknowns that I don't know how to solve for. Any guidance on what to do?

    Thanks
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    anyone?
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    Lol us UCL freshers are pretty desperate for answers
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    (Original post by johnosullivan887)
    Lol us UCL freshers are pretty desperate for answers
    xD I worked out most of the answers in the end so it's OK
 
 
 
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