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# Higher maths help please with the stupidest question watch

1. Hi guys,

Thanks you.
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3. (Original post by rabia999)
Hi guys,

Thanks you.
1. You're not stupid if you're studying higher maths
2. I wish I could be of use but I can't remember this.
4. (Original post by rabia999)
Hi guys,

Thanks you.
Right, I'm not fantastic at explaining things, or at logarithmic graphs. But I must have done something right or I wouldn't have got my Higher Maths this year. And no your not stupid because you don't understand a particular question at first, your studying one of the hardest Highers out there for a start! Anyway...

Logarithmic functions usually pass through the point (1,0), whereas the function in your question passes through (3,0). The line x=2 is given as a little hint. It shows that the graph has been moved to the right by 2 places. Combine this with what you learnt about Graph Transformations then you can work out 'b'.
Spoiler:
Show

b=2

Finding 'a' requires you to sub in a point on the function back into the function, here the point (4,3) is given to you and you should use that. To find 'a' you need to sub in the value you found for 'b' and the x and y values from the coordinates given into the equation in the question.
Spoiler:
Show

a=3

5. I couldn't find a Higher Maths forum so I'll just post it here.

I'm finding Definite Integrals really difficult.
Well, I think I'm doing well but I always check the answers and it's never correct.

It's finding the area under a curve (above and below the x-axis). I was wondering if anybody could help me at all in this topic. Any help is appreciated !
6. (Original post by Ethan100)
I couldn't find a Higher Maths forum so I'll just post it here.

I'm finding Definite Integrals really difficult.
Well, I think I'm doing well but I always check the answers and it's never correct.

It's finding the area under a curve (above and below the x-axis). I was wondering if anybody could help me at all in this topic. Any help is appreciated !
Is this for core 1, because we've just finished doing this in class so I could help
7. (Original post by ruby_zara)
Is this for core 1, because we've just finished doing this in class so I could help
I'm not exactly sure what core 1 includes but I'm guessing it is...
I just want steps on how to answer those types of questions and an example would be also great !
8. You integrate as normal, raise the power by 1 and divide by the new power. once you have you your integrated function you then substitute in your limits.

Ex.

For the area under a graph, its exactly the same steps, except they might ask you to find the limits. In which case you take your y=f(x) and set it to 0 to find the roots/x-intercepts of the graph. That would be your basic questions. If the graph is a mix of under and below the x axis then you MUST do these separately, i.e. find the areas above separately from the areas below because when you find the areas below they will come out as negative. You cant have a negative area so you must make it positive and then add it to the above areas for final answer.

Hope this helps
9. (Original post by Tayls102)
You integrate as normal, raise the power by 1 and divide by the new power. once you have you your integrated function you then substitute in your limits.

Ex.

For the area under a graph, its exactly the same steps, except they might ask you to find the limits. In which case you take your y=f(x) and set it to 0 to find the roots/x-intercepts of the graph. That would be your basic questions. If the graph is a mix of under and below the x axis then you MUST do these separately, i.e. find the areas above separately from the areas below because when you find the areas below they will come out as negative. You cant have a negative area so you must make it positive and then add it to the above areas for final answer.

Hope this helps
That's perfect ! Thanks so much for the effort

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