# Deriving stokes law - Help please!

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15 years ago
#21
(Original post by Squishy)
It's part of my first-year course, although not my main focus (computer science).
do you do physical modelling, in that case?
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15 years ago
#22
(Original post by Squishy)
Good luck .
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15 years ago
#23
(Original post by elpaw)
do you do physical modelling, in that case?
It's not on the first-year course...I'm supposed to study Physics to broaden my first year...I don't think it's supposed to be related to the main subject.

(Original post by Nylex)
Good luck .
Thanks. (3 weeks to go now)
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15 years ago
#24
(Original post by Squishy)
Thanks. (3 weeks to go now)
No prob. I applied, but didn't make it past the interviews, hehe.
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15 years ago
#25
(Original post by Nylex)
No prob. I applied, but didn't make it past the interviews, hehe.
Having seen the workload for next year, I'd say you were lucky.
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15 years ago
#26
Bernoulli's Equation is basically the law of energy conservation applied to incompressible, inviscid flow along a streamline.

Stokes Law for Drag on a Sphere relates the drag coefficient to the Reynolds Number (Re) within the range Re < 1. The Reynolds Number is the ratio of inertial to viscous forces.

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#27
Thats nice of you to help Shiny, but that is WAY beyond Alevel. However, if you could explain the concept of laminar and turbulent flow through a tube to me, that would be great! I want to know why one will result in a different velocity...
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15 years ago
#28
(Original post by RobbieC)
Thats nice of you to help Shiny, but that is WAY beyond Alevel. However, if you could explain the concept of laminar and turbulent flow through a tube to me, that would be great! I want to know why one will result in a different velocity...
I presume you are talking about the loss of pressure through a pipe?

Laminar flow - smooth flow, low loss.
Turbulent flow - likes it sounds is turbulent, lots of eddies and internal mixing, which results in energy dissipation and loss of pressure.

EDIT: Or do you mean differences in velocity profiles?
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#29
(Original post by shiny)
I presume you are talking about the loss of pressure through a pipe?

Laminar flow - smooth flow, low loss.
Turbulent flow - likes it sounds is turbulent, lots of eddies and internal mixing, which results in energy dissipation and loss of pressure.

EDIT: Or do you mean differences in velocity profiles?
Velocity profiles.

Ive decided to do a project where I investigate the difference in the viscosity coefficient at different temperatures.

I was just curious for bg info purposes as to how turbulent flow would prevent a stable equilibrium... Its not clear in my mind.
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15 years ago
#30
(Original post by RobbieC)
Velocity profiles.
It is pretty much the same reasons as for pressure loss. Turbulent flows have a unsteady velocity components which causes mixing and momentum transfer between fluid layers. Consequently a turbulent velocity profile has a steeper velocity gradient near the pipe wall than a laminar flow where there is little momentum transfer between layers (since there is much less flow instability).
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