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    ABCis a triangle and P is any point in BC. If PQ is the resultant of AP,PB,PC show that ABQC is a parallelogram, and Q is therefore fixed point.
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    (Original post by cathedra x)
    ABCis a triangle and P is any point in BC. If PQ is the resultant of AP,PB,PC show that ABQC is a parallelogram, and Q is therefore fixed point.
    Since you've posted several times on the maths forum now, you should be familiar with the guidelines - if not, please read.

    Regarding your question.

    It's a good idea to draw a diagram.

    Since PQ is the resultant of three given vectors, write it as such....(1)

    Then to show it's a parallelogram, you want to show AC=BQ, and AB=CQ

    To show AC= BQ, work out two routes from A to C. One can just be AC, the other needs to incorporate BQ, Set them equal and use (1) to simplify.
 
 
 
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Updated: November 4, 2016
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