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    I forgot how to find the unknown coordinates could anyone explain how to do this
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    (Original post by βradley)
    I forgot how to find the unknown coordinates could anyone explain how to do this
    Its the circled question that I can't remember how to do.
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    The point x = 0, y = k is on the curve, so those values must satisfy the equation of the curve.
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    the point is (0,k). To find the y value, substitute the value of x into the equation.
    It is a 'state' question so it should not really require much/any working.

    It's basically saying, "when x = 0, what is y?"
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    (Original post by surina16)
    the point is (0,k). To find the y value, substitute the value of x into the equation of the circle.
    That's a cubic polynomial...
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    (Original post by RogerOxon)
    The point x = 0, y = k is on the curve, so those values must satisfy the equation of the curve.
    (Original post by surina16)
    the point is (0,k). To find the y value, substitute the value of x into the equation of the circle.
    It is a 'state' question so it should not really require much/any working.

    It's basically saying, "when x = 0, what is y?"
    Thanks im gonna have another try and this thanks for the pointers really appreciated 👍🏼
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    (Original post by RDKGames)
    That's a cubic polynomial...
    sorry i said circle because i was doing maths questions at the same time (which involved circles) :lol:
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    (Original post by βradley)
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    Its the circled question that I can't remember how to do.
    the question is asking you what the y intercept of what the equation is, i.e. the number at the last bit which is -12.
    Another way of looking at the question is to substitute the value of 0 into the equation which also gives -12.
    SIMPLE
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    (Original post by ibk1998)
    the question is asking you what the y intercept of what the equation is, i.e. the number at the last bit which is -12.
    Another way of looking at the question is to substitute the value of 0 into the equation which also gives -12.
    SIMPLE
    Thank you
 
 
 
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