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    1/(cos A+ Sin A) + 1/ (CosA-SinA) = Tan 2a Cosec A

    how please?
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    (Original post by APersonYo)
    1/(cos A+ Sin A) + 1/ (CosA-SinA) = Tan 2a Cosec A

    how please?
    By getting it into one fraction, then using identities and cancelling things down.
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    (Original post by APersonYo)
    1/(cos A+ Sin A) + 1/ (CosA-SinA) = Tan 2a Cosec A

    how please?
    Maybe, try to form a common denominator and make it 1 fraction? .
    Then you'll realise you've eliminated one of the terms in the numerator.
    Then, let's see what you do .
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    remember that E/F + G/H can be written as { ExH + FxG } / { FxH }
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    (Original post by monk1324)
    lhs= (2cosa)/(cos^2a - sin^2a) = 2cosa/cos2a x sina/sina = (2cosasina)/(cos2a) x 1/sina = sin2a/cos2a x 1/sina = tan2a x coseca = rhs


    thank you so so so much!!!
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    (Original post by monk1324)
    LHS= (2cosA)/(cos^2A - sin^2A) = 2cosA/cos2A x sinA/sinA = (2cosAsinA)/(cos2A) x 1/sinA = sin2A/cos2A x 1/sinA = tan2A x cosecA = RHS
    Please don't give full solutions :'(. It is against the rules of the forum.
 
 
 
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