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    What amount of gas takes up 6dm^3 at 102kPa and 25 degrees? Any help would be greatly appreciated!!
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    Use the ideal gas equation, pV = nRT, you're trying to find amount (n) so divide by RT to get n=pV/RT.

    You need to convert the values you have to standard units. 25°C can be converted to 298K by adding 273 . 6dm3 = 6x10-3m3 . You also need to use 102x103Pa, as the value you're given is in kPa. You know that R=8.31JK-1mol-1.

    From here, you can just put the numbers in the formula.
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    (Original post by lizardlizard)
    Use the ideal gas equation, pV = nRT, you're trying to find amount (n) so divide by RT to get n=pV/RT.

    You need to convert the values you have to standard units. 25°C can be converted to 298K by adding 273 . 6dm3 = 6x10-3m3 . You also need to use 102x103Pa, as the value you're given is in kPa. You know that R=8.31JK-1mol-1.

    From here, you can just put the numbers in the formula.
    Thank you very much! When it said 'the amount' I thought it meant the volume, but the volume had already been stated. Thank you for clearing things up for me.
 
 
 
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