Hi all I've missed some of the integration lessons and my revision guide is not helping me with certain questions. I was wondering if I can have help on this question.
The gradient of the curve C is give by dy/dx=(2x-5)^2. The point P (3,1) lies on C. Find the equation of the normal to C at point P.
Then find an equation for the curve C in the form y=f(x).
Then finally using dy/dx=(2x-5)^2 show that there is no point on C at which the tangent is parallel to the line y=7-3x. Many thanks in advance for the help.
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- Thread Starter
- 06-11-2016 20:03
- 06-11-2016 20:10
You already have the gradient of the curve at all points, so finding the normal at P should be easy.
Integrate to find the function. Substitute in the coordinates of P to find the constant.
Assume (2x-5)^2 = 7-3x and find a contradiction.