Hi, I really need help with this question (SMC). Can someone tell me an easy method to do this via combinatorics?
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Maths question help asap pls! watch
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- Thread Starter
- 07-11-2016 14:29
- 07-11-2016 20:42
The way I went about it is by saying: The first fnarg can be one of 6 . The second fnarg can be one of 2 (It must be a different colour, but not the same number heads as the first one (3-1)). The third fnarg can be one of one (It must be the same colour as the first one, but not the same number of heads as the second one). The fourth fnarg can be one of one, The fifth one and the sixth one as well. So you get 6 * 2 * 1 * 1 * 1 * 1 = 12. Am I right?