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    2.5 g of a sample of impure ethanedioic acid, H2C2O4.2H2O, was dissolved in water and the solution made up to 250 cm3. This solution was placed in a burette and 21.3 cm3 were required to neutralise 25 cm3 of 0.1 moldm-3 NaOH. Given that ethanedioic acid reacts with NaOH in a 1:2 ratio, calculate the percentage purity of the sample.
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    (Original post by imaan567)
    2.5 g of a sample of impure ethanedioic acid, H2C2O4.2H2O, was dissolved in water and the solution made up to 250 cm3. This solution was placed in a burette and 21.3 cm3 were required to neutralise 25 cm3 of 0.1 moldm-3 NaOH. Given that ethanedioic acid reacts with NaOH in a 1:2 ratio, calculate the percentage purity of the sample.
    Firstly, work out the number of mole of NaOH that used to neutralize the acid - mole of NaOH = 0.1 x 25/1000
    Secondly, work out the moles of acid in 21.3 cm3, mole of acid in 21.3 cm3 = mole of NaOH/2
    Thirdly, work out the moles of acid in 250cm3 by timing the moles of acid in 21.3 cm3 by 250/21.3
    Fourthly, multiply the mole of acid in 250cm3 by the Mr of the acid to get the mass of acid.
    Lastly, devide the mass by 2.5g and times 100 to get % purity.
    Hope this help😀
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    (Original post by Earth1)
    Firstly, work out the number of mole of NaOH that used to neutralize the acid - mole of NaOH = 0.1 x 25/1000
    Secondly, work out the moles of acid in 21.3 cm3, mole of acid in 21.3 cm3 = mole of NaOH/2
    Thirdly, work out the moles of acid in 250cm3 by timing the moles of acid in 21.3 cm3 by 250/21.3
    Fourthly, multiply the mole of acid in 250cm3 by the Mr of the acid to get the mass of acid.
    Lastly, devide the mass by 2.5g and times 100 to get % purity.
    Hope this help😀
    Thanks a million! I understand it now finally, spent ages on it haha
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    4. 2.5 g of a sample of impure ethanedioic acid, H2C2O4.2H2O, was dissolved in water and the solution made up to 250 cm3. This solution was placed in a burette and 21.3 cm3 were required to neutralise 25 cm3 of 0.1 moldm-3 NaOH. Given that ethanedioic acid reacts with NaOH in a 1:2 ratio, calculate the percentage purity of the sample.
 
 
 
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