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    I will insert the question and my working out so far:
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    Name:  Screen Shot 2016-11-09 at 15.12.54.png
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    Ive so far got up to here:
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    (Original post by Rukia12)

    Ive so far got up to here:
    Should be 2x inside cosine at the end.
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    (Original post by RDKGames)
    Should be 2x inside cosine at the end.
    how to i simplify 2cosxcos pi/3 to cos2x?
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    (Original post by Rukia12)
    how to i simplify 2cosxcos pi/3 to cos2x?
    Again, it should be cos(2x) and not cos(x) in that equation. Apart from that, simply evaluate 2cos(pi/3)
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    You've made a slight mistake in the final step of your working. It should read 2cos(2x)cos(pi/3). cos(pi/3) is 0.5 and you get 2 * 0.5 * cos(2x), which is simply cos(2x).
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    (Original post by RDKGames)
    Again, it should be cos(2x) and not cos(x) in that equation. Apart from that, simply evaluate 2cos(pi/3)
    Oh sorry I didn't understand that earlier !
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    (Original post by wajeeh1364)
    You've made a slight mistake in the final step of your working. It should read 2cos(2x)cos(pi/3). cos(pi/3) is 0.5 and you get 2 * 0.5 * cos(2x), which is simply cos(2x).
    Oh I see, thank you very much !
 
 
 
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