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# Simplifying (32x^5)^-2/5 watch

1. Hi,

I'm trying to simplify (32x^5)^-2/5

I have the written solutions, which says it then goes to (2x)^-2, and then to 1/(4x^2)

I get how (2x)^-2 goes to 1/(4x^2), but how does (32x^5)^-2/5 go to (2x)^-2.

Please can you explain that one step to me?

Thanks
2. (Original post by AnIndianGuy)
1/(4x^2) is equivalent to (2x)^-2. Both are correct.
I know. I am asking how you simplify (32x^5)^-2/5 into 2x^-2
3. (Original post by blobbybill)
Hi,

I'm trying to simplify (32x^5)^-2/5

I have the written solutions, which says it then goes to (2x)^-2, and then to 1/(4x^2)

I get how (2x)^-2 goes to 1/(4x^2), but how does (32x^5)^-2/5 go to (2x)^-2.

Please can you explain that one step to me?

Thanks

Does that help?
4. (Original post by blobbybill)
how does (32x^5)^-2/5 go to (2x)^-2.
Apply the following to your expression:
(a^b)^c = a^(bc)

You should get 32^d, where d is for you to calculate. Note that you can write 32 as a power of 2.

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