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    Hi,

    I'm trying to simplify (32x^5)^-2/5

    I have the written solutions, which says it then goes to (2x)^-2, and then to 1/(4x^2)

    I get how (2x)^-2 goes to 1/(4x^2), but how does (32x^5)^-2/5 go to (2x)^-2.

    Please can you explain that one step to me?

    Thanks
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    (Original post by AnIndianGuy)
    1/(4x^2) is equivalent to (2x)^-2. Both are correct.
    I know. I am asking how you simplify (32x^5)^-2/5 into 2x^-2
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    (Original post by blobbybill)
    Hi,

    I'm trying to simplify (32x^5)^-2/5

    I have the written solutions, which says it then goes to (2x)^-2, and then to 1/(4x^2)

    I get how (2x)^-2 goes to 1/(4x^2), but how does (32x^5)^-2/5 go to (2x)^-2.

    Please can you explain that one step to me?

    Thanks
    (32x^5)^{-\frac{2}{5}} = \left((32x^5)^{\frac{1}{5}} \right) ^{-2} = ...

    Does that help?
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    (Original post by blobbybill)
    how does (32x^5)^-2/5 go to (2x)^-2.
    Apply the following to your expression:
    (a^b)^c = a^(bc)

    You should get 32^d, where d is for you to calculate. Note that you can write 32 as a power of 2.
 
 
 
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